3n=8+[(n+1)+(n+2)]

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Solution for 3n=8+[(n+1)+(n+2)] equation:


Simplifying
3n = 8 + [(n + 1) + (n + 2)]

Reorder the terms:
3n = 8 + [(1 + n) + (n + 2)]

Remove parenthesis around (1 + n)
3n = 8 + [1 + n + (n + 2)]

Reorder the terms:
3n = 8 + [1 + n + (2 + n)]

Remove parenthesis around (2 + n)
3n = 8 + [1 + n + 2 + n]

Reorder the terms:
3n = 8 + [1 + 2 + n + n]

Combine like terms: 1 + 2 = 3
3n = 8 + [3 + n + n]

Combine like terms: n + n = 2n
3n = 8 + [3 + 2n]

Remove brackets around [3 + 2n]
3n = 8 + 3 + 2n

Combine like terms: 8 + 3 = 11
3n = 11 + 2n

Solving
3n = 11 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
3n + -2n = 11 + 2n + -2n

Combine like terms: 3n + -2n = 1n
1n = 11 + 2n + -2n

Combine like terms: 2n + -2n = 0
1n = 11 + 0
1n = 11

Divide each side by '1'.
n = 11

Simplifying
n = 11

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